MathIQO worksheet
Solve problems involving the volume of prisms and pyramids · Grade 9 · E1.6
Name: ______________________
Date: ______________________
- 1
Find the volume of a rectangular prism with length 2 cm, width 5 cm, and height 9 cm, in cm³.
Warm-upAnswer:
- 2
Find the volume of a rectangular prism with length 8 cm, width 2 cm, and height 9 cm, in cm³.
Warm-upAnswer:
- 3
Find the volume of a rectangular prism with length 2 cm, width 4 cm, and height 6 cm, in cm³.
Warm-upAnswer:
- 4
A triangular prism has a triangular face with base 8 cm and height 8 cm, and a length of 8 cm. Find its volume, in cm³.
On levelAnswer:
- 5
A triangular prism has a triangular face with base 8 cm and height 5 cm, and a length of 3 cm. Find its volume, in cm³.
On levelAnswer:
- 6
A triangular prism has a triangular face with base 10 cm and height 5 cm, and a length of 4 cm. Find its volume, in cm³.
On levelAnswer:
- 7
Find the volume of a rectangular-based pyramid with a 7 cm by 2 cm base and height 9 cm, in cm³.
ChallengeAnswer:
- 8
Find the volume of a rectangular-based pyramid with a 8 cm by 7 cm base and height 12 cm, in cm³.
ChallengeAnswer:
- 9
Find the volume of a rectangular-based pyramid with a 6 cm by 5 cm base and height 3 cm, in cm³.
ChallengeAnswer:
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Worksheet code: eyJzIjoiZ2VvbWV0cnktdm9sdW1lLXByaXNtLXB5cmFtaWQiLCJkIjpbOTczODkwMjIzLDEyOTI2MjMzNDUsMTY2MjgxNjgwNyw1NzYxMjk1NjAsNzU0NDY5MjIsMTM5ODk0NTI1Nyw1MjY3OTY5NDQsMTkzMDgzMjc4LDE5MjgyMTg4MjddLCJ2IjoxfQ.22e6b836abb9
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Answer key · Solve problems involving the volume of prisms and pyramids
- 1.90 — V = l × w × h = 2 × 5 × 9 = 90 cm³.
- 2.144 — V = l × w × h = 8 × 2 × 9 = 144 cm³.
- 3.48 — V = l × w × h = 2 × 4 × 6 = 48 cm³.
- 4.256 — Base area = (8 × 8) ÷ 2 = 32 cm², so V = 32 × 8 = 256 cm³.
- 5.60 — Base area = (8 × 5) ÷ 2 = 20 cm², so V = 20 × 3 = 60 cm³.
- 6.100 — Base area = (10 × 5) ÷ 2 = 25 cm², so V = 25 × 4 = 100 cm³.
- 7.42 — V = (l × w × h) ÷ 3 = (7 × 2 × 9) ÷ 3 = 42 cm³.
- 8.224 — V = (l × w × h) ÷ 3 = (8 × 7 × 12) ÷ 3 = 224 cm³.
- 9.30 — V = (l × w × h) ÷ 3 = (6 × 5 × 3) ÷ 3 = 30 cm³.